Rectangle Problem
Given:
$\text{One side} = 7\text{ cm}, \quad \text{Diagonal} = 25\text{ cm}$
Using Pythagoras’ Theorem:
$25^2 = 7^2 + x^2$
$625 = 49 + x^2$
$x^2 = 625 – 49 = 576$
$x = \sqrt{576} = 24$
$\boxed{\text{Other side} = 24\text{ cm}}$
Given:
$\text{One side} = 7\text{ cm}, \quad \text{Diagonal} = 25\text{ cm}$
Using Pythagoras’ Theorem:
$25^2 = 7^2 + x^2$
$625 = 49 + x^2$
$x^2 = 625 – 49 = 576$
$x = \sqrt{576} = 24$