Exercise 3.1 – Q3 Solution
Question
Write the cubes of all natural numbers between 1 and 10 and verify the following statements:
- Cubes of all odd natural numbers are odd.
- Cubes of all even natural numbers are even.
Solution
| Number | Cube |
|---|---|
| 1 | \(1^3=1\) |
| 2 | \(2^3=8\) |
| 3 | \(3^3=27\) |
| 4 | \(4^3=64\) |
| 5 | \(5^3=125\) |
| 6 | \(6^3=216\) |
| 7 | \(7^3=343\) |
| 8 | \(8^3=512\) |
| 9 | \(9^3=729\) |
| 10 | \(10^3=1000\) |
Verification
(i) Cubes of all odd natural numbers are odd:
Odd numbers: \(1,3,5,7,9\)
Their cubes are: \(1,27,125,343,729\)
All these numbers are odd.
Hence, the cubes of all odd natural numbers are odd.
(ii) Cubes of all even natural numbers are even:
Even numbers: \(2,4,6,8,10\)
Their cubes are: \(8,64,216,512,1000\)
All these numbers are even.
Hence, the cubes of all even natural numbers are even.
Exercise 3.1 – Q4 Solution
Question
Write the cubes of 5 natural numbers which are multiples of 3 and verify the following statement:
“The cube of a natural number of the form \(3n+1\) is a natural number of the same form.”
Solution
Five multiples of 3: \(3,\;6,\;9,\;12,\;15\)
| Number | Cube |
|---|---|
| 3 | \(3^3=27\) |
| 6 | \(6^3=216\) |
| 9 | \(9^3=729\) |
| 12 | \(12^3=1728\) |
| 15 | \(15^3=3375\) |
Verification of the Statement
Take five natural numbers of the form \(3n+1\):
\(1,\;4,\;7,\;10,\;13\)
| Number | Cube | Form |
|---|---|---|
| 1 | 1 | \(3\times0+1\) |
| 4 | 64 | \(3\times21+1\) |
| 7 | 343 | \(3\times114+1\) |
| 10 | 1000 | \(3\times333+1\) |
| 13 | 2197 | \(3\times732+1\) |
Hence, the cube of a natural number of the form \(3n+1\) is also of the form \(3n+1\). Therefore, the statement is verified.
Exercise 3.1 – Q5 Solution
Question
Write the cubes of 5 natural numbers which are multiples of 7 and verify the following statement:
“The cube of a multiple of 7 is a multiple of \(7^3\).”
Solution
Five multiples of 7: \(7,\;14,\;21,\;28,\;35\)
| Number | Cube | Division by \(343\) |
|---|---|---|
| 7 | 343 | \(343=343\times1\) |
| 14 | 2744 | \(2744=343\times8\) |
| 21 | 9261 | \(9261=343\times27\) |
| 28 | 21952 | \(21952=343\times64\) |
| 35 | 42875 | \(42875=343\times125\) |
Since every cube is exactly divisible by \(343=7^3\), the cube of every multiple of 7 is a multiple of \(7^3\).
Hence, the statement is verified.